Estimate the van der Waals constant ano tor gas andGas… (2023)

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Estimate the van der Waals constant ano tor gas andGasIK 866.6 722.1PLatm 355.6 74.1(Latm/molz)b (L/mol)Which gas's behavior is expected to be more ideal? Which gas has the higher attractive intermolecular forces? Which has the larger excluded molecular volume?

Estimate the van der Waals constant ano tor gas and Gas IK 866.6 722.1 PLatm 355.6 74.1 (Latm/molz) b (L/mol) Which gas's behavior is expected to be more ideal? Which gas has the higher attractive intermolecular forces? Which has the larger excluded molecular volume?

Estimate the van der Waals constant ano tor gas andGas… (1)
Estimate the van der Waals constant ano tor gas andGas… (2)

Chemistry 101

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Erom the values in Table $5.3$ for the van der Waals constant $a$ for the gases $\mathrm{H}_{2}, \mathrm{CO}_{2}, \mathrm{~N}_{2}$, and $\mathrm{CH}_{4}$, predict which of these gas molecules show the strongest intermolecular attractions.

In problem number 32. The question wants us to identify which of the two given mark molecules would have a larger Vander wal's constant be. So if we look at the two molecules, I'm going to write their molecular formulas. The first molecule is methane CH four and the second molecule has five carbons in it. So that is painting C five, age 12. So the one that is going to have the larger Vander wal's constant be is going to be the pen tane. Mhm. Okay. The reason for that is because the larger the molecule, the larger its constant be, the constant B is based upon the volume of the molecule. So the bigger molecule, the bigger the constant be, so larger molecule equals larger beat. So this was based entirely upon the size of these two molecules. Alright, thanks for watching.

Hi there. In this question, we are given four substances and we want to know which of those has the strongest inter molecular attraction between its molecules. Um, the way we're going to do this is we're going to compare the Vander Wal constants for these. So let's get started doing that. I'm going to be consulting Table 8-3 and first I'm going to look up hydrogen. It's constant is 2.4 point 244 Next, his carbon dioxide with a constant of 3.59 Do we have nitrogen? Constant is 1.39 and finally methane with a constant of 2.25 So to determine the one with the strongest inter molecular attraction between its molecules, we're looking for the one that has the highest Vander Wal's constant, and that is going to be the carbon dioxide. So the carbon dioxide has the strongest inter molecular attraction between its molecules. Alrighty. Thank you so much for watching

Problem, 37 says from the values and table 5.3 for the Vander Wal's Constant A for the gases hydrogen, carbon dioxide, nitrogen and methane. Which of the gases would you protect? Shows strongest intern molecular interactions. So this a constant here, um, from Table 5.3 is a pressure constant for gases based on observed behaviors. So in this table wth E a constant for hydra truths for hydrogen gas, this 0.2 for four carbon dioxide is 3.59 nitrogen gas is 1.39 and methane is 2.25 So this pressure calculation this a factor is subtracted from the more ideal gas pressure based on the inter molecular attractions off gas molecules, UM, that are observed that would, in essence, prevent the expected number of collisions with the container. So pressure is basically the force of gas molecules against their container. And so these experimental values we're determined and subtract from tthe e ideal gas law equation because increased inter molecular reactions decreases the number off interactions between gas molecules and their container. So because this is a distraction, it means that the largest number, the furthest away from the ideal gas scenario probably has the strongest inter molecular attractions. That means that carbon dioxide here with the largest number is probably the gas with E strongest inter molecular, um, forces.

In this problem, we want to determine whether neon or crypt on gas has a larger value for the A constant in the vander Waals equation. The general trend to keep in mind is that both of the A M B constants in the Vander Waals equation or dependent upon the identity of the gas specifically, both of these constants A and B increase as the molar mass or mu of the gas increases. If we look at the periodic table, we see that the molar mass of neon is about 20.18 grams per mole in the molar mass of Krypton is about 84.8 grams per mole. When we compare these two, we see that krypton has a greater more mass than neon. And according to this relationship, we can conclude that the a constant for Krypton has a larger value than the A constant or neon

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